WebLCM and HCF Aptitude Easy Questions and Answers Page - 27. Download App. Academic Resource. Aptitude Data Interpretation ... (6905– 4665) and (6905 – 1305) = HCF of 3360, 2240 and 5600. Correct Option: A. We can say that the largest number which when divide the numbers a, b and c give remainders as p, q, r respectively is given by H.C.F ... WebOct 21, 2024 · As it is given in the question that we have to find the largest N so it means that we have to find the largest number that divides all of (3360,5600,and 2240) which means that we have to find the HCF of all these numbers The HCF of 3360,2240,5600 is 1120 so our N=1120 the sum of digits of N is 1+1+2+0=4 Advertisement Still have …
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WebSep 16, 2024 · Math Secondary School answered Hcf of 3360,2240,5600 See answers Advertisement Unknown000 1120 is the answer Hope it's help u Advertisement … WebSteps to simplifying fractions Find the GCD (or HCF) of numerator and denominator GCD of 448 and 1120 is 224 Divide both the numerator and denominator by the GCD 448 ÷ 224 1120 ÷ 224 Reduced fraction: 2 5 Therefore, 448/1120 simplified to lowest terms is 2/5. MathStep (Works offline) ghostbusters banshee
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WebJul 2, 2024 · 4665 - 1305 = 3360 6905 - 4665 = 2240 6905 - 1305 = 5600 HCF of 3360, 2240 and 5600 = 1120 Then sum of the digits in N = 1 + 1 + 2 + 0 = 4 ∴ The sum of the digits in N is 4 Download Solution PDF Latest Odisha … Webclass notes HCF-pg1.1 - Read online for free. class notes on HCF and LCM. class notes on HCF and LCM. Documents; Teaching Methods & Materials; ... [4665 - 1305, 6905 - 4665, 6905 - 1305] N = HCF [3360, 2240, 5600] = 1120 Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4 The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 ... Web= H.C.F. of 3360, 2240 and 5600 = 1120. Sum of digits in N = (1 + 1 + 2 + 0) = 4 Aren't we supposed to find the HCF (1305, 4665, 6905) rather than that of the HCF(4665 - 1305), … from weakest to world\u0027s strongest anime